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Neat Calculus Proof: Derivative of x·sin⁻¹(x) + √(1−x²) = sin⁻¹(x)
In this video, we solve a derivative problem involving inverse sine (arcsin) and show that: 👉 If y = x × sin⁻¹(x) + √(1 − x²), then the derivative dy/dx = sin⁻¹(x). We’ll apply the product rule, chain rule, and some neat cancellations to arrive at the final result. Perfect for students preparing for JEE, IB Math, AP Calculus ...
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