\(2x^2 – 7x – 4\) factorises as \((2x + 1)(x – 4)\). \((2x + 1)(x – 4) = 0\). \(2x + 1 = 0 \) means \(x = -\frac{1}{2}\). \(x – 4 = 0\) means \(x = 4 ...
For tips on how to do this, look at Factorising quadratics and Factorisation of further quadratics in this guide. For (\({x}\) + 2)(\({x}\) + 7) to equal 0 either the first or second bracket must be ...
Looking for the answers to ax² + bx + c = 0? A mathematician has rediscovered a technique that the ancient Babylonians used. By Kenneth Chang and Jonathan Corum The quadratic equation has frustrated ...
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