Simon Fraser University

Section 6.12 Exponential Growth and Decay

(a)\(\ds \frac{dA}{dt}=pA\text{,}\) \(A(0)=A_0\text{;}\) \(A=A_0e^{pt}\text{.}\) (b) Solve \(15,000=10,000\cdot e^{4p}\) (a) \(\ds \frac{dA}{dt}=k(M-A(t))\text ...